Question

A cubical box with lid has a length of 30 cm. Find the cost of painting the inside and outside of the box at 5.50 per m^2.
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Answer 1

Answer:

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Step-by-step explanation:

We have to find the surface area of the cubical box.

Surface area of the cube = 6a² where a = 30 cm

⇒ 6*30*30

⇒ 5400 sq cm

As the cubical box has to be painted both from the outside and inside.

So, the total surface area = Inner surface area + outer surface area

⇒ 5400 + 5400

= 10800 sq cm

As we know that 1 sq m = 10000 sq cm

Surface area in sq m = 10800/10000

Surface area in sq m = 1.08 sq m

Cost of painting the cubical box = Rs. 5.50 per sq m

Total cost of painting = 5.5*1.08

Total cost = Rs. 5.94

So, the total cost of painting the cubical box from outside and inside is 5.94

Answer 2

Answer:

Length of edge of cube =30 cm = 30/100m

Total area of painting=Inside Area + Outside area

=2×T.S.A of Cube

$2 \times {6a}^{2}$

$12 \times( \frac{30}{100} )^{2}$

$12 \times \frac{30}{100} \times \frac{30}{100}$

$\frac{108}{100} = 1.08 {m}^{2}$

$cost \: of \: 1 {m}^{2} = ₹5.50$

$cost \: of \: 1.08 {m}^{2 } = ₹5.50 \times 1.08$

$= ₹5.94$