A cubical cake of side 16 cm is cut into 8 cubes of equal volume. What will be the side of the new cube? Also find the ratio between their surface areas.
Answers
Given data : A cubical cake of side 16 cm is cut into 8 cubes of equal volume.
- cubical side of cake = 16 cm
- volume of cake = ?
Solution :
Firstly we have to find volume of cubical cake.
⟹ volume of cubical cake = (side)³
⟹ volume of cubical cake = 16³
⟹ volume of cubical cake = 4096 cm³ ----{1}
Now,
⟹ surface area of cubical cake = 6 * (side)²
⟹ surface area of cubical cake = 6 * (16)²
⟹ surface area of cubical cake = 6 * 256
⟹ surface area of cubical cake = 1536 cm² ----{2}
Here, we know that cubical cake is cut into 8 cubes of equal volume.
Now,
⟹ volume of new cubical cakes = 4096/8
⟹ volume of new cubical cakes = 512 cm³
Now, to find side of new cubical cakes .
⟹ volume of new cubical cakes = (side)³
⟹ 512 = (side)³
⟹ side = ³√512
⟹ side = 8 cm
Now,
⟹ surface area of new cubical cakes = 1536/8
⟹ surface area of new cubical cakes = 192 cm²
Now,
⟹ surface area of cubical cake : surface area of new cubical cake = 1536 : 192
⟹ surface area of cubical cake : surface area of new cubical cake = 8 : 1
Answer : The side of the new cubical cake is 8 cm and ratio of surface area of cubical cake to new cubical cake is 8 : 1.