Question

a cubical container is side l completely filled with water horizontal acceleration to container so that half of total volume of water out come out from​

Answer 1

As the given side of cubical container is I.

• Let the V be the volume the water in container.

• According to the statement the spilled water V=I³×1/2
• The surface dip height be h
• The volume of spilled liquid = area of triangle×side of cube
• That is $\frac{1}2}$×h×I²
• $\frac{1}{2}$×I³=$\frac{1}{2}$×h×I²
• On solving we get I=h
• The angle made by surface with horizontal be Ф
• That tanФ=a/g
• h/I=a/g
• Using above relation we get g=a
• That is the answer