Question

A cubical die whose faces are numbered from 1 to 6is rolled once the probability of getting a number on the top of face which is a multiple of 3 is

Answer 1

Answer:

There are 6 numbers in a die, in which two of them are multiples of 3. They are 3 and 6.

So,the probability of getting a number on the top of face which is a multiple of 3 is 2/6 (or) 1/3.

Answer 2

Answer:

Step-by-step explanation:

Sample space,S={1,2,3,4,5,6}

Let E be the event that denotes the multiple of 3 on the top of cube face.

Multiples of 3 are

3,6

E={3,6}

Favorable cases=2

Total number of cases=6

Probability,P(E)=$\frac{favorable\;cases}{Total\;number\;of\;cases}$

Using the formula

The probability of getting a number on the top of face which is a multiple of 3=$\frac{2}{6}$

The probability of getting a number on the top of face which is a multiple of 3=$\frac{1}{3}$

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