Question

a cubical piece of wood has length 10 cm and breadth 8cm . how high it must be made to hold 720 cubic cm of liquid​

Answer 1

Answer:

-by-step explanation:

{\rm{\fbox{\pink{Given,}}}}

Given,

Area = 340m²

Breadth = 17m

{\rm{\fbox{\blue{To \: find,}}}}

To find,

Length

Perimeter

{\Large{\bf{\green{Finding \: length:}}}}Findinglength:

Area = length × breadth

⇒340 = length × 17

⇒340/17 = length

⇒20 = length

.°. Length of the rectangle = 20m

{\Large{\bf{\orange{Finding \: perimeter:}}}}Findingperimeter:

Perimeter = 2(length + breadth)

⇒Perimeter = 2(20m+17m)

⇒Perimeter = 40m + 34m

⇒Perimeter = 74m

.°. Perimeter of the rectangle = 74m

Hence, Length and perimeter of the rectangle is 17m and 74m respectively

Answer 2

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in the question it is given that there is a cubical piece of wood whose length is 10 cm and the breadth of the cubical piece of wood is 8 cm and we need to find the height that it must be made to hold 720 cubic centimetre of liquid

So , Let's solve it !!!

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$\begin{gathered}\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\\\;\underbrace{\underline{\sf{Answer:-}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered} \end{gathered}$

the cubical piece of wood must be 9cm high to hold 720 cubic cm of liquid

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$\begin{gathered}\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\\\;\underbrace{\underline{\sf{Given:-}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered} \end{gathered}$

volume of cubical piece of wood = 720 cm³

length of cubical piece of wood = 10 cm

breath of cubical piece of wood = 8 cm

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height of cubical piece of wood = ?

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$\begin{gathered}\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\\\;\underbrace{\underline{\sf{Solution:-}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered} \end{gathered}$

let the height of cubicle piece of wood be h

volume of cuboidal piece of wood = l × b × h

↝720 = 10 × 8 × h

↝720 = 80h

↝h = 720 / 80

↝h = 9