a cubical solid of metal has lenght,breadthand height as 40cm,30cm and 25 cm.If this solid is melted and recasted into solid cubes each of side 5 cm,find the number of cubes formed.
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Length = 40 cm
Breadth = 30 cm
Height = 25 cm
Volume of the cuboidal metal solid = lbh
= 40 x 30 x 25
= 30000 cm^3
Volume obtained Cubical box by melting = 6a^3
= 6 x 5 x 5 x 5
= 750 cm^3
Number of cubes obtained = Initial volume / final volume
= 30000/750
Ans: = 40
Therefore number of cubes = 40.
Hope this helped you. And please confirm with ur teachers or any experts here if any wrong I have done. I think the sum is correct!. :-)
Breadth = 30 cm
Height = 25 cm
Volume of the cuboidal metal solid = lbh
= 40 x 30 x 25
= 30000 cm^3
Volume obtained Cubical box by melting = 6a^3
= 6 x 5 x 5 x 5
= 750 cm^3
Number of cubes obtained = Initial volume / final volume
= 30000/750
Ans: = 40
Therefore number of cubes = 40.
Hope this helped you. And please confirm with ur teachers or any experts here if any wrong I have done. I think the sum is correct!. :-)
Hisana:
Plss.. mark as the bzt! :-)
volume is a^3.
Answered by
0
It is a cuboid with dimension
length = 40 cm
breadth = 30 cm
height = 25 cm
Volume(V)= lbh = 40×30×25 = 30000 cm³
Dimension of small cube obtained after recast is 5cm
volume(v) = a³ = 5³ = 125 cm³
Number of cubes= V/v = 30000/125 = 240
So total 240 cubes can be obtained.
length = 40 cm
breadth = 30 cm
height = 25 cm
Volume(V)= lbh = 40×30×25 = 30000 cm³
Dimension of small cube obtained after recast is 5cm
volume(v) = a³ = 5³ = 125 cm³
Number of cubes= V/v = 30000/125 = 240
So total 240 cubes can be obtained.
sorryy.. I have written the TSA 6a^2 as 6a^3..
your's is correct!
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