Question

A cubical steel block of side 5.0 cm exerts a pressure of 4000 Pascal when placed on a plane surface. Calculate the weight of the block.

Answer 1

P=F/A
F=P×A
=4000×25CM SQ
=4000×25×1/10000
=10N
SO WEIGHT will also equal to 10N

hope you like my answer

Answer 2

Side of the cubical box = 5 cm = 5×10^-2 m

Pressure = P = 4000 Pa

Area of the block = l² = (5×10^-2)² = 25×10^-4 m²

P = F/A , so :

F = P×A

F = 4000× 25 × 10^-4 = 10 N

The required weight = 10 N


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