a cubical tank of 3.0 M is evacuated of air. that is the number of molecules of air inside the tank is insignificant compared to the number in the same volume outside the atmospheric pressure is 10 raise to power 5 Pascal what is the crushing force exerted by the atmosphere on the tank?
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P = F / A where
P is the pressure exerted on a body, F the force and A the area where the force is exerted.
The area of the cube is:
3 × 3 × 6 = 54M²
F = Pressure × Area
From the question:
Pressure = 10⁵ N/M²
Force = 10⁵ × 54
5400000N
P is the pressure exerted on a body, F the force and A the area where the force is exerted.
The area of the cube is:
3 × 3 × 6 = 54M²
F = Pressure × Area
From the question:
Pressure = 10⁵ N/M²
Force = 10⁵ × 54
5400000N
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2
Explanation:
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