a cubical tank of side 1.5 m is filled with water calculate the thrust of water on the bottom and on a vertical side take g =10 m/s2
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Pressure (P) at the bottom of the tank is given by P=hdg
=1m×1000kg×9.8ms−2=9800Nm−2
Surface area at the bottom of the tank =2m×1.5m=3m2
∴Thrustatthebottomofthetank=force×area
=9800Nm−2×3m2=29,400N.
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