A cubical tank of side 1m is filled with 800kg of a liquid (1 ) find the volume of tank (2) the density of liquid
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Explanation:
Solution:
(i) The volume of a cube = side\times side\times sideside×side×side
Side of the cubical tank side = 1 m
Therefore, volume = 1\ m\ \times1\ m\ \times1\ m1 m ×1 m ×1 m
(ii) The density of liquid in kg\ m^{-3}kg m
−3
= \frac{Mass}{Volume}
Volume
Mass
Mass = 800 kg
Volume = 1\ m^31 m
3
d = \frac{800}{1}=800\ kg\ m^3
1
800
=800 kg m
3
Answered by
0
Answer:
(i) The volume of a cube = side\times side\times sideside×side×side
Side of the cubical tank side = 1 m
Therefore, volume = 1\ m\ \times1\ m\ \times1\ m1 m ×1 m ×1 m
(ii) The density of liquid in kg\ m^{-3}kg m−3 = \frac{Mass}{Volume}VolumeMass
Mass = 800 kg
Volume = 1\ m^31 m3
d = \frac{800}{1}=800\ kg\ m^31800=800 kg m3
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