Physics, asked by imdranisarkar568, 26 days ago

A cubical tank of side 1m is filled with 800kg of a liquid (1 ) find the volume of tank (2) the density of liquid​

Answers

Answered by reevachauhan18
2

Explanation:

Solution:

(i) The volume of a cube = side\times side\times sideside×side×side

Side of the cubical tank side = 1 m

Therefore, volume = 1\ m\ \times1\ m\ \times1\ m1 m ×1 m ×1 m

(ii) The density of liquid in kg\ m^{-3}kg m

−3

= \frac{Mass}{Volume}

Volume

Mass

Mass = 800 kg

Volume = 1\ m^31 m

3

d = \frac{800}{1}=800\ kg\ m^3

1

800

=800 kg m

3

Answered by harjotchauhan2008
0

Answer:

(i) The volume of a cube = side\times side\times sideside×side×side

Side of the cubical tank side = 1 m

Therefore, volume = 1\ m\ \times1\ m\ \times1\ m1 m ×1 m ×1 m

(ii) The density of liquid in kg\ m^{-3}kg m−3 = \frac{Mass}{Volume}VolumeMass

Mass = 800 kg

Volume = 1\ m^31 m3

d = \frac{800}{1}=800\ kg\ m^31800=800 kg m3

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