Question

A cubical tank of side 2m each is filled with water.

Calculate the force on the bottom of the tank (density of water = 1000kg/m3 )​

Answer 1

Explanation:

Volume of cubical tub = Length X Breadth X Height Here,

length = breadth = height = 2 m

Volume = 2x2x2 = 8 ${{m}^{3}}$

Mass of water = Volume X Density of water = 8 X 1000 = 8000 kg

.’. Weight of water = Mass X Acceleration due to gravity = 8000 X 10 = 8 X${{10}^{4}}$ N

.’. Total thrust = Weight of water = 8 X 104 N (i) Area of bottom = Area of square shape of tub = 2x2 = 4 ${{m}^{2}}$

.’. Pressure or water at the bottom =Force / Area = Weight / Area = 8 x ${{10}^{4}}$ / 4 = 2 x ${{10}^{4}}$ N

Answer 2

Answer:

F = mg = 1000 x 8 x 10 = 8 x 10^4