Question

A cubical tank whose side is 2m is filled with water. The water from cubical tank is shifted to a cuboidal tank whose lenght, breadth and height are 250cm, 200cm and 2m respectively. Find the depth of tank which will remain empty.

Answer 1

volume of water in cubical tank = a³ = 2³ =8cm³
Dimensions of cuboid ,
l = 2.5 m
b = 2 m
h = 2m

volume of cuboid = lbh = 2.5 × 2 × 2 = 10 cm ³

volume of cuboid left when water is poured from cubical tank = 10 - 8 = 2cm³

2.5 × 2 × h = 2
h = $\frac{1}{2.5}$
h = $\frac{1}{\frac{5}{2}}$
h = $\frac{2}{5}$
h = 0.4 m
the depth of tank which will remain empty = 0.4 m

Answer 2

Find the volume of the water:

Volume = Length³

Volume = 2³

Volume = 8 m³

Find the height of the water in the cuboidal tank:

Volume = Length x Breadth x Height

8 m³ = 250 cm x 200 cm x Height

8 m³ = 2.5m x 2m x Height

8 = 5 x height

Height = 8 ÷ 5 = 1.6 m

Find the depth of the tank that remain empty:

Depth = 2 m - 1.6 m = 0.4 m

Answer: The depth without water is 0.4 m