A cubical vessel has a side with'1' cm length contained a pressure 'p 'when the side of the vessel is
vhpsharitha:
sorry, I didn't complete the question
when the side of the vessel becomes 1/2
the the pressure becomes
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cubic vessel (with face horizontal + vertical) contains an ... 1 mole of an ideal gas is contained in a cubical volume V, ... P = Pressure of gas, n = Number of moles
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Answer: the answer comes up to be 8 times p
Explanation:
According to Boyle's law,
PV is constant
As a cubical vessel is considered, its volume comes after be L³
So, p 1 v 1 is equal to p 2 v 2
Pl³= P2 (l³/8)
And then P2 comes up to be 8p.
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