A cubical vessel of heigh 1 m is full with water. The minimum work done in taking water-out from vessel will be
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The amount of work done in taking water-out from vessel will be 5000 J
Explanation:
The height of cubical vessel "h" = 1 m
Work done = mgh/2
Density of water = mass = 10^3 Kgm^3
Work done = 10^3 x 10 x 1/2
= 1000 x 10 x 0.5
= 1000 x 5 = 5000 J
Thus the amount of work done in taking water-out from vessel will be 5000 J
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