A cubical vessel of height 1m is full of water. The minimum work done in taking water out from vessel will be? *please explain clearly*
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Work = Change in Potential energy
= Final Potential energy - Initial Potential energy
= mgL - mgL/2
= mgL/2
= (ALd gL)/2
= (1^2 * 1 * 10^3 * 10 * 1)/2
= 5 kJ
= Final Potential energy - Initial Potential energy
= mgL - mgL/2
= mgL/2
= (ALd gL)/2
= (1^2 * 1 * 10^3 * 10 * 1)/2
= 5 kJ
atulkaushal484:
From where this l/2 came?
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