Physics, asked by atulkaushal484, 1 year ago

A cubical vessel of height 1m is full of water. The minimum work done in taking water out from vessel will be? *please explain clearly*

Answers

Answered by Anonymous
8
Work = Change in Potential energy

= Final Potential energy - Initial Potential energy

= mgL - mgL/2

= mgL/2

= (ALd gL)/2

= (1^2 * 1 * 10^3 * 10 * 1)/2

= 5 kJ

atulkaushal484: From where this l/2 came?
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