Physics, asked by adrisaha20, 9 months ago

A cubical vessel with open top of side length 1m is
filled with water. Now it start moving with constant
acceleration 19.6 m/s2 in horizontal direction. Then
the amount of water split out is​

Answers

Answered by bestwriters
6

The amount of water split out is​ 1000 kg.

Explanation:

In pseudo equilibrium, the angle of water with the horizontal surface be θ

On resolving the pseudo and gravitational force along the surface of water, we get,

a cos θ = g sin θ

tan θ = a/g

On substituting the values, we get,

tan θ = 19.6/9.8 = 2

The volume of the water spilled out is:

V = 1/2 × (1 × tan θ) × 1 × 1

On substituting the values, we get,

V = 1/2 × 2 = 1 m³

∴ V = 1000 kg

Answered by agrawalbhumika79
1

Answer:

Explanation:

The amount of water split out is​ 1000 kg.

Explanation:

In pseudo equilibrium, the angle of water with the horizontal surface be θ

On resolving the pseudo and gravitational force along the surface of water, we get,

a cos θ = g sin θ

tan θ = a/g

On substituting the values, we get,

tan θ = 19.6/9.8 = 2

The volume of the water spilled out is:

V = 1/2 × (1 × tan θ) × 1 × 1

On substituting the values, we get,

V = 1/2 × 2 = 1 m³

∴ V = 1000 kg

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