A cubical vessel with open top of side length 1m is
filled with water. Now it start moving with constant
acceleration 19.6 m/s2 in horizontal direction. Then
the amount of water split out is
Answers
The amount of water split out is 1000 kg.
Explanation:
In pseudo equilibrium, the angle of water with the horizontal surface be θ
On resolving the pseudo and gravitational force along the surface of water, we get,
a cos θ = g sin θ
tan θ = a/g
On substituting the values, we get,
tan θ = 19.6/9.8 = 2
The volume of the water spilled out is:
V = 1/2 × (1 × tan θ) × 1 × 1
On substituting the values, we get,
V = 1/2 × 2 = 1 m³
∴ V = 1000 kg
Answer:
Explanation:
The amount of water split out is 1000 kg.
Explanation:
In pseudo equilibrium, the angle of water with the horizontal surface be θ
On resolving the pseudo and gravitational force along the surface of water, we get,
a cos θ = g sin θ
tan θ = a/g
On substituting the values, we get,
tan θ = 19.6/9.8 = 2
The volume of the water spilled out is:
V = 1/2 × (1 × tan θ) × 1 × 1
On substituting the values, we get,
V = 1/2 × 2 = 1 m³
∴ V = 1000 kg