Question

A cubical wooden box floating on water rises 2cm when 200 gm of stone is removed from it. What will be length of side of this box?

Answer 1

Answer:

Let edge length of cube be x cm

Volume of water displaced by 200 g object is 2x^2cm3

Mass of 200gm block =Mass of water displaced

200g=V d

$200g = 2 {x}^{2} {cm}^{3} \times 1 \frac{g}{ {cm}^{3} }$

$x = \sqrt{ \frac{200}{2} }$

x=10

length of side of this box=10cm.