Question

A cubicle block of wood has side 8cm.its specific gravity is 0.6.Find the height of block outside the surface.​

Answer 1

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GiVen:

Side of cube =8cm

Specific Gravity = $\rho_s$ =0.6

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ForMula:

• $\rho_s =\dfrac{V_{submerged\:solid}}{V_{Total}}$
• Volume of cube = a³

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SoluTion:

Let the Side not submerged in liquid be x

$\rho_s =\dfrac{V_{submerged\:solid}}{V_{Total}}$

$\implies$ $0.6 =\dfrac{\cancel{8^2}(8-x)}{\cancel{8^3}}$

$\implies$ $\dfrac{\cancel6}{\cancel{10}}=\dfrac{8-x}{a}$

$\implies$$\dfrac{3}{5} =\dfrac{8-x}{a}$

By Cross Multiplying

$\implies3a =5a-5x\\ \\ 5x=5a-3a \\ \\ x = \dfrac{2a}{5} \\ \\ \boxed{x = 3.2cm}$