A cubiod has total surface 372 cm² and its lateral surface area is 189 cm², find the area and its base
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total surface area of the cuboid is given by 2 ( lb + bh + lh)
hence 2 ( lb + bh + lh ) = 372 sq
lateral surface area is given by 2 ( hl + hb)
2 ( hl + hb) = 188 sq cm
2 ( lb + bh + lh ) = 372 sq
ie 2lb + 2bh + 2hl = 372
2lb + 2( hl + hb) = 372
2lb + 189 = 372
2lb = 372 - 189 = 183
2lb = 183
lb = 91.5 sq cm
hence, the area of the base of this cuboiud is 91.5 sq cm
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