a cubodical block of metal meausring 60 cm x 40 x 50 cm find the total surface area of the cubiod
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Answer:
Total surface area =2(lb+bh+lh)
=2(60×40+40×50+50×60)c.m²
=2(2400+2000+3000)
=2(7400)
=14800cm²
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Step-by-step explanation:
Given :
length = 60 cm
breadth = 40 cm
height = 50 cm
Volume of Cuboid = 2 x (lb+bh+hl)
=2 × (60×40+40×50+50×40)
=2 × 6400
= 12,800 cm
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