Math, asked by prabalsaha124, 3 months ago

A cuboid container has the capacity to hold 50 small boxes. If all the dimensions of the container are doubled, then it can hold (small boxes of same size)

Answers

Answered by Itzishi
4

Answer:

8 time of the 50 small boxes

=8×50

=400

Answered by swethassynergy
2

A cuboid container has the capacity to hold 50 small boxes. If all the dimensions of the container are doubled, then it can hold 400 boxes.

Given,

Initial capacity = 50

To find,

Total number of boxes after dimensions are doubled.

Solution,

Let the dimensions of cuboid be = length × breadth × height = l × b × h.

After dimensions are doubled = 2l × 2b × 2h.

Initial Volume = lbh

Final Volume = 8lbh

Since, the final volume is eight times the initial the total number of boxes to fit in final container would be (8)(50) = 400.

Therefore, if all the dimensions of the container are doubled, then it can hold 400 boxes.

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