A cuboid container has the capacity to hold 50 small boxes. If all the dimensions of the container are doubled, then it can hold (small boxes of same size)
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Answer:
8 time of the 50 small boxes
=8×50
=400
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A cuboid container has the capacity to hold 50 small boxes. If all the dimensions of the container are doubled, then it can hold 400 boxes.
Given,
Initial capacity = 50
To find,
Total number of boxes after dimensions are doubled.
Solution,
Let the dimensions of cuboid be = length × breadth × height = l × b × h.
After dimensions are doubled = 2l × 2b × 2h.
Initial Volume = lbh
Final Volume = 8lbh
Since, the final volume is eight times the initial the total number of boxes to fit in final container would be (8)(50) = 400.
Therefore, if all the dimensions of the container are doubled, then it can hold 400 boxes.
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