a cuboid has dimension 27 CM 18 cm and 9 cm It is melted and recast into in tentacle cube of side 9 cm find the number of cubes obtained
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volume of cuboid= n× volume of cube
where n is nomber of cubes.
27×18×9=n×9×9×9
486=n×81
486÷81=n
6=n
answer........
where n is nomber of cubes.
27×18×9=n×9×9×9
486=n×81
486÷81=n
6=n
answer........
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vol . of cuboid = l*b*h
= 27*18*9
vol. of cube = a*a*a
= 9*9*9
vol. of cuboid = vol of cube * n (n = no. of cubes)
27*18*9 = 9*9*9*n
n = 2*3
n = 6
therefore 6 cubes can be obtained .
= 27*18*9
vol. of cube = a*a*a
= 9*9*9
vol. of cuboid = vol of cube * n (n = no. of cubes)
27*18*9 = 9*9*9*n
n = 2*3
n = 6
therefore 6 cubes can be obtained .
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