a cuboid has total surface area of 40 m square and lateral surface area of 26 m square .find the area of its base.
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the area of the base of the cuboid is 7 square m
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Lateral surface area = 26m²
Lateral surface area = 2 h ( l + b ) = 2lh + 2bh or
lateral surface area = 2(lh + bh )
26 = 2(lh + bh )
26/2 = lh + bh
Total surface area = 2( lb + bh + lh )
40/2 = lb + bh + lh
20 = lb + lh + bh
substituting the values,
we have,
lb + bh + lh = 20
lh + bh + lb = 20
13 + lb = 20
lb = 20 - 13
lb = 7
The base area is 7m²
Lateral surface area = 2 h ( l + b ) = 2lh + 2bh or
lateral surface area = 2(lh + bh )
26 = 2(lh + bh )
26/2 = lh + bh
Total surface area = 2( lb + bh + lh )
40/2 = lb + bh + lh
20 = lb + lh + bh
substituting the values,
we have,
lb + bh + lh = 20
lh + bh + lb = 20
13 + lb = 20
lb = 20 - 13
lb = 7
The base area is 7m²
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