a cuboid has total surface area of 80m and its lateral surface area is 56m. find area of its base
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Answered by
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Hey there !!
➡ Given :-
→ TSA of cuboid = 40 m² .
→ LSA of cuboid = 26 m² .
➡ To find :-
→ Area of the base .
▶ Answer:
We have,
LSA of cuboid = 26m² .
=> 2( l + b )h = 26 .
=> 2lh + 2bh = 26 ............(1) .
▶Now,
TSA of cuboid = 40m² .
=> 2( lb + bh + hl ) = 40 .
=> 2lb + 2bh + 2hl = 40 .
=> 2lb + 26 = 40. [ Using (1) . ]
=> 2lb = 40 - 26 .
=> 2lb = 14 .
=> lb = 14/2 .
•°• lb = 7 m² .
✔✔ Hence, area of base is 7 m² ✅✅.
THANKS
#BeBrainly.
➡ Given :-
→ TSA of cuboid = 40 m² .
→ LSA of cuboid = 26 m² .
➡ To find :-
→ Area of the base .
▶ Answer:
We have,
LSA of cuboid = 26m² .
=> 2( l + b )h = 26 .
=> 2lh + 2bh = 26 ............(1) .
▶Now,
TSA of cuboid = 40m² .
=> 2( lb + bh + hl ) = 40 .
=> 2lb + 2bh + 2hl = 40 .
=> 2lb + 26 = 40. [ Using (1) . ]
=> 2lb = 40 - 26 .
=> 2lb = 14 .
=> lb = 14/2 .
•°• lb = 7 m² .
✔✔ Hence, area of base is 7 m² ✅✅.
THANKS
#BeBrainly.
Anudeerp:
14/7 is not equal to 7
Answered by
0
given
total surface area = 80m^2
=2(lb+bh+ lb)=80m^2
lb+ bh +lb=40 m^2________(1)
lateral surface area =52 m^2
2h (l+b) = 26m^2
lb+bh =26m^2_____(2)
substitute (2) in(1)
lb + 26 =40m^2
lb=14m^2
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