Question

a cuboid of dimension 10 cm by 2 cm by 2 cm is divided into 5 cubes of edge 2 cm. find the ratio of the total surface area of the cuboid and that of the cubes

Answer 1

surface area of cuboid = 2 (lb+bh+hl)
=2 (10×2+2×2+10×2)
=2 (20+4+20)
2 (44)=
88 cm^2
surface area of cube = 6l^2
= 6 (()2)^2
=6 (4)
24cm^2
total surface area of cube = 5 (24)
120cm^2
ratio = 88cm^2/120cm^2
11:15
hope it helps you to

Answer 2

Volume of cuboid = 10*2*2=40 cm^3
So Volume of each of 5 cubes = 40/5=8 cm^3
Side of each cube = cuberoot (8) = 2 cm
Surface area of cuboid = 2(20+20+4)= 88 cm^2
Surface area of each cube = 6*4 = 24 cm^2
Total surface area of the cubes is 5*24=120 cm^2
So the ratio of the total surface area of the cuboid and that of the cubes = 88:120 = 11 :15