Question

A cuboid of dimensions 10cm by 2cm by 2cm is divided into 5 cubes of edge 2 cm. Find the ratio of the total surface area of the cuboid and cube​

Answer 1

Answer:

Dimensions of Cuboid = 10 by 2 by 2 cm Therefore, Volume of Cuboid = 10 x 2 x 2 = 40 cm³ Since it is divided into 5 cubes, Volume of each Cube, l³ = 40/5 = 8 cm³ Therefore, Length of each side of cube, l = ³√8 = 2 cm Now, Total Surface Area of Cuboid = 2(lb + bh + hl) TSA = 2(10x2 + 2x2 + 2x10) = 2(20 + 4 + 20) = 2(44) ..

Answer 2

Answer:

11:15

Step-by-step explanation:

Total surface area of cuboid

= 2(10x2 + 10x2 + 2x2)

= 2(20+20+4)

= 2(44)

= 88 cm^3

Total surface area of one cube

= 6x(2x2)

= 6x4

= 24 cm ^3

For 5 cubes total surface area = 5x24 = 120

Ratio = surface area of cuboid / surface area of 5 cubes

Ratio = 88/120

= 11/15

=11:15

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