A Cuboid of dimensions 5cm ,3cm and 2cm
Answers
Answered by
16
Volume of cuboid= l*b*h
= 5*3*2
=30 cm^3
total surface area= 2(lb+bh+hl)
= 2(15+6+10)
=2(31)
=62cm^2
= 5*3*2
=30 cm^3
total surface area= 2(lb+bh+hl)
= 2(15+6+10)
=2(31)
=62cm^2
Answered by
5
Hey there!
I guess your question is a cuboid of dimensions 5, 3 , 2 cm is melted to form a cube, Find the side of largest cube so formed.
While a solid object in transformed to the other , it volume remains unchanged.
Volume = 5 * 3 * 2 = 30 cm² .
Volume of largest cube is less than or equal to Volume of cuboid.
Let the side of cube = a
V(cube) ≤ V(cuboid)
a³ ≤ 30
a = { 3 , 2 , 1 ... -∞ }
As we want the side of largest cube, 3 is the largest possible real value.
Therefore, Side of required cube = 3 cm.
I guess your question is a cuboid of dimensions 5, 3 , 2 cm is melted to form a cube, Find the side of largest cube so formed.
While a solid object in transformed to the other , it volume remains unchanged.
Volume = 5 * 3 * 2 = 30 cm² .
Volume of largest cube is less than or equal to Volume of cuboid.
Let the side of cube = a
V(cube) ≤ V(cuboid)
a³ ≤ 30
a = { 3 , 2 , 1 ... -∞ }
As we want the side of largest cube, 3 is the largest possible real value.
Therefore, Side of required cube = 3 cm.
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