a cuboid of lenght 16 cm ,breath 12 cm ,height 20 cm is melted down to form a sphere fin the radius of the sphere
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1
Since volumes will remain unchanged , therefore ,
lbh = 4/3 πR³
16×12×20 = 4/3 π R³
3840 × 3 / 4 =π R³
2880/π = R³
lbh = 4/3 πR³
16×12×20 = 4/3 π R³
3840 × 3 / 4 =π R³
2880/π = R³
asr1:
is it a correct answer
Answered by
5
volume of cuboid = volume of sphere
Length × Breadth × Height = 4/3 r cube
16×12×20 = 4/3 x 22/7 x r x r x r
3840 = 88/21 x r x r x r
3840 x 21/88 =r x r x r
80640/88 =r x r x r
916.36 = r cube
Length × Breadth × Height = 4/3 r cube
16×12×20 = 4/3 x 22/7 x r x r x r
3840 = 88/21 x r x r x r
3840 x 21/88 =r x r x r
80640/88 =r x r x r
916.36 = r cube
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