Question

A cuboid of volume 128 cm cubic is divided in to two equal cubes. the sum of total surface area of two cubes is

Answer 1

hello users  ......

Solution:-
we know that :-
volume of cube = a³

where a is the side of cube .

and
surface area of cube = 6a²

Here,
According to given :
volume of one cube is equal to half of volume of cuboid.

=> volume of cube = 128 / 2 = 64 cm³

=> a³ = 4³
=> a = 4 cm 

Now ,
The surface area of one cube = 6 * 4²
= 16 * 6
= 96 cm²

=> the surface area of two cubes = 2 * surface area of cube 

=> 2 * 96 = 192 cm² Answer 

# hope it helps :)

Answer 2

Hey,

Volume of cuboid =128cm^3
Divided into two part it become two equal cube.
So, volume of each cube =128/2cm^3
=64cm^3
Now,
a^3=64cm^3
a=4cm
. now t. S. A of cube
=6a^2
Two equal cube area

=2*6a^2
=2*6*4^2

=192m^2 Ans.

@rajukumar