Question

A cuboid tin open at the top has dimensions 20cm×16cm×14cm.what is the total area of a sheet of metal required to make 10 such tins.​

Answer 1

Answer:

Step-by-step explanation:

As we have to Find the Metal Sheet Required to make 10 Cuboidal Tin Box. For that we will find TSA of 1 Cuboidal Tin Box.

Given Dimensions Are :

Length = 20 cm

Breadth = 16 cm

Height = 14 cm

• Total Surface Area of Cuboidal Box :

⇒ TSA = 2(lb + bh + hl)

⇒ TSA = 2(20 × 16 + 16 × 14 + 14 × 20)

⇒ TSA = 2(320 + 224 + 280)

⇒ TSA = 2 × 824

⇒ TSA = 1648 cm²

• Total Area of Metal Sheet Required :

⇒ Total Sheet Required = TSA × Boxes

⇒ Total Sheet Required = 1648 cm² × 10

⇒ Total Sheet Required = 16480 cm²

we have to change it into m² accrⁿ Question

⇝ 16480 cm²

⇝ 16480 /100 × 100 m²

⇝ 1648 /1000 m²

⇝ 1.648 m²

∴ 1.648 m² Metal Sheet Required for 10 Box

Answer 2

Answer: 1.328m²

Step-by-step explanation: Area of the cuboid tin= 2(lb+bh+hl)-l*b

=2(320cm²+224²+280²) - 320cm²

= 2*824cm² - 320cm²

= 1648cm² - 320cm²

= 1328cm²(area of 1 tin)

1328cm²*10

= 13280cm²

10000cm² = 1m²

= 1.328m²