a cuboid whose Total surface area is 50 m² And curved surface area is 30² find area of base
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Total surface area = 50 m² (Given)
Total Surface area = 2 x base area + curved surface area
2 x base area + 30 = 50
2 x base area = 50 - 30
2 x base area = 20
base area = 20 ÷ 2 = 10 m²
Answer: Base area = 10 m²
rounaksingh33:
ok i know that thanks again
Answered by
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HELLO FRIEND HERE IS YOUR ANSWER,,,,,,
A Cuboid of Total Surface are is
= 50![{m}^2 {m}^2](https://tex.z-dn.net/?f=%7Bm%7D%5E2+)
The formula for Total Surface area of a Given Cuboidal Surface
= 2 × Area of Base + Total Curved Surface Area
By substituting the given values of Total Surface area of Cuboid and Total Curved Surface Area,,, we get ,,,,
![= > 50 \: {m}^{2} = 2 \times Area \: \: Of \: \: Base \: + 30 \: {m}^{2} \\ \\ = > 50 \: {m}^{2} - 30 \: {m}^{2} = 2 \times Area \: \: Of \: \: Base \\ \\ = > 20 \: {m}^{2} = 2 \times \: Area \: \: Of \: \: Base \\ \\ = > \frac{20 \: {m}^{2} }{2 \: {m}^{2} } = Area \: \: Of \: \: Base \\ \\ = > Area \: \: Of \: \: Base \: = \: 10 \: {m}^{2} = > 50 \: {m}^{2} = 2 \times Area \: \: Of \: \: Base \: + 30 \: {m}^{2} \\ \\ = > 50 \: {m}^{2} - 30 \: {m}^{2} = 2 \times Area \: \: Of \: \: Base \\ \\ = > 20 \: {m}^{2} = 2 \times \: Area \: \: Of \: \: Base \\ \\ = > \frac{20 \: {m}^{2} }{2 \: {m}^{2} } = Area \: \: Of \: \: Base \\ \\ = > Area \: \: Of \: \: Base \: = \: 10 \: {m}^{2}](https://tex.z-dn.net/?f=+%3D+%26gt%3B+50+%5C%3A+%7Bm%7D%5E%7B2%7D+%3D+2+%5Ctimes+Area+%5C%3A+%5C%3A+Of+%5C%3A+%5C%3A+Base+%5C%3A+%2B+30+%5C%3A+%7Bm%7D%5E%7B2%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+50+%5C%3A+%7Bm%7D%5E%7B2%7D+-+30+%5C%3A+%7Bm%7D%5E%7B2%7D+%3D+2+%5Ctimes+Area+%5C%3A+%5C%3A+Of+%5C%3A+%5C%3A+Base+%5C%5C+%5C%5C+%3D+%26gt%3B+20+%5C%3A+%7Bm%7D%5E%7B2%7D+%3D+2+%5Ctimes+%5C%3A+Area+%5C%3A+%5C%3A+Of+%5C%3A+%5C%3A+Base+%5C%5C+%5C%5C+%3D+%26gt%3B+%5Cfrac%7B20+%5C%3A+%7Bm%7D%5E%7B2%7D+%7D%7B2+%5C%3A+%7Bm%7D%5E%7B2%7D+%7D+%3D+Area+%5C%3A+%5C%3A+Of+%5C%3A+%5C%3A+Base+%5C%5C+%5C%5C+%3D+%26gt%3B+Area+%5C%3A+%5C%3A+Of+%5C%3A+%5C%3A+Base+%5C%3A+%3D+%5C%3A+10+%5C%3A+%7Bm%7D%5E%7B2%7D+)
Which is the required solution for this type of query.
HOPE IT HELPS YOU AND CLEARS YOUR DOUBTS FOR CUBOIDAL AREA OF BASE!!!!
A Cuboid of Total Surface are is
= 50
The formula for Total Surface area of a Given Cuboidal Surface
= 2 × Area of Base + Total Curved Surface Area
By substituting the given values of Total Surface area of Cuboid and Total Curved Surface Area,,, we get ,,,,
Which is the required solution for this type of query.
HOPE IT HELPS YOU AND CLEARS YOUR DOUBTS FOR CUBOIDAL AREA OF BASE!!!!
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