Question

A cuboidal block has a volume of 20 cm3 and mass of 800 g. Calculate its:
(i) Density in the CGS system. (i) Density in the SI system.
(ii) Relative density.​

Answer 1

Answer:

Here ,mass m =100 kg,

density p=500kgm

-3

volume of body ,V=

p

m

=

500

100

=0.2m

3

weight of water displaced

=Vpg

=0.2×10

3

×g

= 200gkgwt

Mass of water displaced 200kg

Explanation:

Therefore, the additional mass which can be added to body,so that body can sink.

=200-100=100kg

Answer 2

sorry siso ♡

Solution:

Given:

Mass of block = 3.5kg => weight of the body = 3.5kgf

Volume of the water displaced when completely immersed in water = 1000cm3

(i) To find the volume of the body when completely immersed in liquid is equivalent to the

volume of the water displaced

Volume of the block = 1000 cm3

or 0.001m3

(ii) Upthrust acting on the body = volume of the body x density of water x g

= 0.001 x 1000 x g = 1 kgf

(iii) The apparent weight of body in water= true weight – upthrust

=3.5-1 = 2.5kgf

hope it helps you ☆