A cuboidal block of weight 1000N with dimension 100 cm x 50cm x 20cm is placed on a surface. Calculate the pressure exerted by block the surface in different orientation.
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Answer:
1000Nm^2
Step-by-step explanation:
To find:
The pressure exerted by the block.
Given:
Weight/Force = 1000N
Dimensions = 100cm x 50cm x 20cm
Formula used:
pressure= Force/area
= 1000/(100/100) x (50/100) x(20/100)
(Since dimensions are in cms we are converting it to m by dividing them by hundred)
=1000/(1 x 1/2 x 1/5)
= 1000 x 2 x 5
= 10000 Nm^2
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