Question

a cuboidal box has age 10cm and another cubical box is 12.5 cm long 10 cm and 8 cm height
1. which box has the greater lateral surface area by how much
2. which has the smaller total surface area by​

Answer 1

Step-by-step explanation:

Answer

(i) Lateral surface area of cube = 4edge2

=4(10)2=400

lateral surface area of cuboid =2h(l+b)

2×8(12.5+10)=16×22.5=360

So, the lateral surface area of the cube is larger by (400−360=40)cm2

(ii) Total surface area of cube = 6edge2

=6(10)2=600

lateral surface area of cuboid =2(lb+bh+hl)

2(12.5×10+10×8+8×12.5)=2(125+80+100)=610

So, the total surface area of cuboid is larger by (610−600=10) cm2

Answer 2

Answer:

(i) Lateral surface area of cube = 4edge  2

=4(10) 2

=400

​lateral surface area of cuboid =2h(l+b)

2×8(12.5+10)

=16×22.5

=360

​ So, the lateral surface area of the cube is larger by (400−360=40)cm

(ii) Total surface area of cube = 6edge  2  

=6(10)  2

=600

​lateral surface area of cuboid =2(lb+bh+hl)

2(12.5×10+10×8+8×12.5)

=2(125+80+100)

=610

​So, the total surface area of cuboid is larger by (610−600=10) cm  2

Step-by-step explanation:

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