a cuboidal box has each edge of 10 cm and another cuboidal box has 12.5 cm long 10 cm wide and 8 cm high which box has greater LSA and by how much
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Answer:
first cuboid
by 40
Step-by-step explanation:
LSA OF CUBOID=2h (l+w)
first cuboid =2×10 (10+10)
=20 (20)
=400
second cuboid=2×8(12.5+10)
=16 (22.5)
=360
so,400-360=40
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