Question

a cuboidal box is 2 metre long 1 m broad and 0.5 m high find the cost of painting its outer surface at the rate of rupees 200 per m square

Answer 1

Answer:

₹1400

Step-by-step explanation:

TSA of cuboidal box = 2(lb+bh+lh)

                                  = 2(2*1 + 1*0.5 + 2*0.5)

                                  =2(2 + 0.5 + 1)

                                  =2 * 3.5

                                  =7m²

Cost of painting = ₹200 * 7m²

                           =₹ 1400

Answer 2

The cost of painting its outer surface at the rate of rupees 200 per m square is Rs.1400

Step-by-step explanation:

Length of cuboidal box = 2m

Breadth of cuboidal box = 1 m

Height of cuboidal box = 0.5 m

Total surface area of box = $2(lb+bh+hl)=2(2 \times 1 + 1 \times 0.5 + 0.5 \times 2)= 7m^2$

Cost of painting 1 sq,m, = Rs.200

Cost of painting 7 sq.m. = $7 \times 200 = Rs.1400$

Hence  the cost of painting its outer surface at the rate of rupees 200 per m square is Rs.1400

#Learn more:

The dimensions of a cuboidal box of 6 m into 400 cm and 2.5 M find the cost of painting its entire outer surface at the rate of rupees 22 m square

https://brainly.in/question/7994623