. A cuboidal box of base measurements 40 cm x 30 cm is kept on the floor. The mass of the box is 120 kg. What is the pressure exerted by the box on the floor?
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Answered by
0
Step-by-step explanation:
The magnitude of the pressure(P) exerted by an object on a given surface is equal to its weight(F) acting in the direction perpendicular to that surface divided by the total surface area of contact(A) between the object and the surface.
P=
A
F
=
a
2
F
where a is the dimension of the cube.
Given that a=50 cm=0.5 m,F=25 N
⟹P=
0.5×0.5
25
⟹P=100 Pa
Answered by
1
Answer:
Hey mate...✨
Step-by-step explanation:
p= 100pa
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