A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be painted.
Spam nhi krne ka wrna
10 answers reported badly
Answers
✧ Question :
- A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be painted.
✧ Given :
- Length of the box, l = 2 m
- Breadth of box, b = 1 m
- Height of box, h = 1.5 m
✧ To Find :
- How much area of the box have to be painted
✧ Solution :
Area of the bottom of the cuboid = L × B
= 1 × 2
= 2 m²
As we know that, The surface area of a cuboid = 2(lb + lh + bh)
But here the bottom part is not to be painted.
Surface area of box to be painted = 2(lb + lh + bh)
= 2 ( 1 × 2 + 2 × 1.5 + 1.5 × 1 )
= 2 ( 2 + 3 + 1.5 )
= 2 + 6.5
= 13 m²
According to the question ( Bottom of the box isn't painted ).
Area of the box painted = (13 -) m² = 11 m²
Hence, the required surface area of the cuboidal box = 11 m2
Area of the bottom of the cuboid = L × B
= 1 × 2
= 2 m²
As we know that, The surface area of a cuboid = 2(lb + lh + bh)
But here the bottom part is not to be painted.
Surface area of box to be painted = 2(lb + lh + bh)
= 2 ( 1 × 2 + 2 × 1.5 + 1.5 × 1 )
= 2 ( 2 + 3 + 1.5 )
= 2 + 6.5
= 13 m²
According to the question ( Bottom of the box isn't painted ).
Area of the box painted = (13 -) m² = 11 m²
Hence, the required surface area of the cuboidal box = 11 m2