Question

A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be painted.

DONOT SPAM
SPAM = 20 ANSWER REPORED

Answer 1

Answer:

$\huge \dag \mathbb {\boxed{QUESTION}}$

A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be painted.

$\mathbb \purple{REQUIRED \: ANSWER}$

Given :

Length of cuboid (l) = 1 m

Breadth of cuboid (b) = 2 m

Height of cuboid (h) = 1.5 m

To Find :

Area of the box that has to be painted.

Some important formulae :

Total surface area of cuboid = 2(lb+bh+hl)

Lateral surface area of cuboid = 2h(l+b)

Solution :

Area of bottom of cuboid = l×b

= 1×2

= 2 m²

And,

Total surface area = 2(lb+bh+hl)

= 2(1×2+2×1.5+1.5×1)

= 2(2+3+1.5)

= 2×6.5

= 13 m²

According to the question the bottom of the box is not painted, then

Area of box painted = (Total surface area - bottom area)

Area of box painted = (13 - 2) m² = 11 m².

• Therefore, 11 m² of area of box is painted.

____________________

• Hopes it was helpful : )

Answer 2

Answer:

$\huge\colorbox{red}{Question}$

A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be painted.

TO FIND :

The area of box is painted.

SOLUTION :

Length of the box, l = 2 m,

Breadth of box, b = 1 m

Height of box, h = 1.5 m

We know that the surface area of a cuboid. = 2(lb + lh + bh)

But here the bottom part is not to be painted.

So,

Surface area of box to be painted = lb + 2(bh + hl)

= 2 × 1 + 2 (1 × 1.5 + 1.5 × 2)

= 2 + 2 (1.5 + 3.0)

= 2 + 9.0

= 11

Hence, the required surface area of the cuboidal box = 11 m².

FINAL ANSWER :

The area of the painted box is 11m².

$\huge\colorbox{pink}{Thanks}$

Hope it helps you...

$\huge\colorbox{orange}{Keep Asking}$