A cuboidal container is 40 cm long and 30 cm wide. It contains water to a height of 11 cm. Some more water was added to it. The water level rose to 14 cm. How much water was added?
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Given,
Length = 40cm
Breadth = 30cm
Height = 11cm
Let 11cm be H(1) and 14cm be H(2)
Now Volume of Container When height is 11cm (Vol.1) = l × b × h
= 40 × 30 × 11
= 13200cm^3
Volume of Container When Height is 14cm (Vol.2) = l × b × h
= 40 × 30 × 14
= 16800cm^3
Hence,Volume of Water Added = 【Vol.2】 - 【Vol.1】
= 16800 - 13200
= 3600cm^3
Given,
Length = 40cm
Breadth = 30cm
Height = 11cm
Let 11cm be H(1) and 14cm be H(2)
Now Volume of Container When height is 11cm (Vol.1) = l × b × h
= 40 × 30 × 11
= 13200cm^3
Volume of Container When Height is 14cm (Vol.2) = l × b × h
= 40 × 30 × 14
= 16800cm^3
Hence,Volume of Water Added = 【Vol.2】 - 【Vol.1】
= 16800 - 13200
= 3600cm^3
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