A Cuboidal fish tank has a length of 30 cm , 20 cm and a height of 20 cm . The tank is placed on a horizontal table and it is three - quarters full of water . Find the area of the tank which is in contact with water
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Dimensions of Cuboidal fish tank:
Length L = 30 cm. Breadth = B = 20 cm. Height = H = 20 cm
If the tank is 3/4 th full of water, it means that it is filled up to 3/4th of its height.
So water is filled upto h = 20 cm * 3/4 = 15 cm.
Surface area of the floor (base) of the tank
= L * B = 30 * 20 = 600 cm²
Surface area of the walls of the tank up to height = h = 15 cm:
= 2 L h + 2 B h
= 2 * 30 cm * 15 cm + 2 * 20 cm * 15 cm
= 1500 cm²
Total surface area of the tank in contact with water
= 600 + 1500
= 2, 100 cm²
Length L = 30 cm. Breadth = B = 20 cm. Height = H = 20 cm
If the tank is 3/4 th full of water, it means that it is filled up to 3/4th of its height.
So water is filled upto h = 20 cm * 3/4 = 15 cm.
Surface area of the floor (base) of the tank
= L * B = 30 * 20 = 600 cm²
Surface area of the walls of the tank up to height = h = 15 cm:
= 2 L h + 2 B h
= 2 * 30 cm * 15 cm + 2 * 20 cm * 15 cm
= 1500 cm²
Total surface area of the tank in contact with water
= 600 + 1500
= 2, 100 cm²
kvnmurty:
:-)
nice solution
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