a cuboidal fish tank of lenght 30 cm breadth 20 cm and height 20 cm. the tank is placed on a horizontal table and it is three quarters full of water. Find the area of the tank which is in contact with water.
Answers
Answered by
19
dimensions of fish tank=30 cm×20 cm×20 cm
volume of tank=12000 cm ³
volume of water=¾×12000=9000 cm ³
height of water level is given by,
lbh=volume of tank
30×20×h=9000
=>h=15
then, surface area=2[(20×15)+(30×15)]+(30×20)=2100 cm ²
volume of tank=12000 cm ³
volume of water=¾×12000=9000 cm ³
height of water level is given by,
lbh=volume of tank
30×20×h=9000
=>h=15
then, surface area=2[(20×15)+(30×15)]+(30×20)=2100 cm ²
Answered by
6
Dimensions of Cuboidal fish tank:
Length L = 30 cm. Breadth = B = 20 cm. Height = H = 20 cm
If the tank is 3/4 th full of water, it means that it is filled up to 3/4th of its height.
So water is filled upto h = 20 cm * 3/4 = 15 cm.
Surface area of the floor (base) of the tank
= L * B = 30 * 20 = 600 cm²
Surface area of the walls of the tank up to height = h = 15 cm:
= 2 L h + 2 B h
= 2 * 30 cm * 15 cm + 2 * 20 cm * 15 cm
= 1500 cm²
Total area in contact with water
= 600 + 1500
= 2, 100 cm²
Length L = 30 cm. Breadth = B = 20 cm. Height = H = 20 cm
If the tank is 3/4 th full of water, it means that it is filled up to 3/4th of its height.
So water is filled upto h = 20 cm * 3/4 = 15 cm.
Surface area of the floor (base) of the tank
= L * B = 30 * 20 = 600 cm²
Surface area of the walls of the tank up to height = h = 15 cm:
= 2 L h + 2 B h
= 2 * 30 cm * 15 cm + 2 * 20 cm * 15 cm
= 1500 cm²
Total area in contact with water
= 600 + 1500
= 2, 100 cm²
kvnmurty:
:-)
Similar questions