Question

A cuboidal ice block is melting such that its height becomes 1/2 of initial heigh
breadth becomes 1/3 rd, and length becomes 1/4 th . Find the ratio of initial
to the volume after melting answer

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Answer 1

Step-by-step explanation:

The volume of the ice cube is 0.001 m 3

so the mass of the ice is 0.001×900=0.9kg

So when after melting, the Ice become water the volume will be 1000/0.9 = 0.0009kg

So the excess volume of the cube that was above the water is 0.001−0.0009 = 0.0001M³

So the excess volume of the cube that was above the water is 0.001−0.0009 = 0.0001M³

after the ice becomes water it will fit into the volume that was inside the water and hence the change in the potential energy will for the portion that was outside the water. The height of the portion is 0.001/0.0001 =0.01m

Now the potential energy for a rectangular slab of height h and area A is P=Aρg²h²

Putting the values of the parameter we get P=0.001×900×9.8×2/0.01²=0.0045.

Hence potential energy will be reduced by 0.0045J.

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