a cuboidal metal plate of 1 cm thickness 9 CM breath and 81 cm length is melted into 1 you find the total surface area of the cube
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Answered by
54
vol of cuboid=l*b*h=1*9*81=729cm³
vol. of cube=vol. of cuboid....
a³=l*b*h
729=a³
a=9cm....
now SA=6*a²
=6*9*9=81*6=486cm²....ans
vol. of cube=vol. of cuboid....
a³=l*b*h
729=a³
a=9cm....
now SA=6*a²
=6*9*9=81*6=486cm²....ans
Answered by
19
Thickness of cuboid = 1 cm
Breath of cuboid = 9 cm
Length of cuboid = 81 cm
Volume = l*b*h
Volume = 1*9*81 = 729 cm ^3
Volume of cube = volume of cuboid
a ^3 = 729
a = √729
a = 9 cm
Surface area = 6a^2
=6(9)^2
= 6*81 = 486cm^2
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