A cuboidal oil tin has dimensions 30cm * 40cm * 50cm . Find the cost of the tin required for making 20 such tins , if the cost of tin sheet is rupee 20 per m square .
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Length = 30cm
Breadth = 40 cm
Height = 50 cm
Total surface area of cuboidal oil tin
= 2 (lb + bh + lh)
= 2 (30×40 + 40×50 + 30×50)
= 2 × 4700
= 9400 cm^2 = 0.94 m^2 = tin required for 1 oil tin
tin required for making 20 oil tins = 0.94 × 20 = 18.8m^2
cost of 1m^2 tin sheet = Rs 20
cost of 120 m^2 tin sheet = 20 × 18.8
= Rs 376
Ans. Cost of tin = Rs 376
Breadth = 40 cm
Height = 50 cm
Total surface area of cuboidal oil tin
= 2 (lb + bh + lh)
= 2 (30×40 + 40×50 + 30×50)
= 2 × 4700
= 9400 cm^2 = 0.94 m^2 = tin required for 1 oil tin
tin required for making 20 oil tins = 0.94 × 20 = 18.8m^2
cost of 1m^2 tin sheet = Rs 20
cost of 120 m^2 tin sheet = 20 × 18.8
= Rs 376
Ans. Cost of tin = Rs 376
angadkhangura13:
But it's answer given is rupee 376 .
what
the answer is Rs 376 ?
it is wrong brother my answer is the correct one
Rs 2400 is correct
sorry brother
I am wrong
don't report it
I am correcting the answer
now it is correct
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