Question

a cuboidal oil tin is of dimension 30 cm* 40 cm * 50 cm . Find the cost of tin required for making 20 such tins if the cost of tin sheet is 20 rs per m ^ 2​

Answer 1

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Cuboid:-

Length of the cuboid tin = 30cm

Breadth of the cuboid tin = 40 cm

Height of the cuboid tin = 50 cm

To find:-

Cost required for making 20 tins with length, breadth and height of 30 cm, 40 cm and 50 cm respectively.

Solution:-

Let's first calculate the total surface area of one tin,

Total surface area = 2(lb + bh + hl)

Total surface area = 2 (30 × 40 + 40 × 50 + 50 × 30)

Total surface area = 2 (1200 + 2000 + 1500)

Total surface area = 2 (4700)

Total surface area = 9400 cm²

•°• total surface area of one tin with dimension 40 × 30 × 50 is 9400 sq.cm

Now multiply the total surface area of one tin with 20 tins.

Total surface area of 20 tins = 20 × 9400

Total surface area of 20 tins = 188000 cm²

As the cost of tin sheet is 20 rs per m² we need to change the unit of total surface area of 20 tins to m²

1m = 100 cm

1m² = (100 × 100)cm

1m² = 10000

•°•total surface area of 20 tins expresssd in m² is,

= $\bf\frac{\cancel{188000}}{\cancel{10000}}$

= 18.8m²

Total surface area of 20 such tins = 18.8m²

cost of one square of tin sheet is 20 rs per m²

•°• cost 18.8m² of tin sheet = 20 × 18.8

= 376

•°•cost of making 20 cuboid tins of dimension 30cm × 40cm × 50cm is ₹ 376.

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Answer 2

The cost of tin required for making 20 such tins is Rs. 18.8

• A cuboid is a three-dimensional object that is surrounded by six rectangular planes of varying length, breadth, and height. Anything in the shape of a rectangle, such as a box, brick, or other object, could be a cuboid if you look about. When viewed from any of the ends, a cuboid (3-dimensional) can be seen to be constructed of different-sized rectangles (2-dimensional).
• A cuboid has six faces, each of which is a rectangle with all four corners at 90 degrees. It has 12 edges and 8 vertices. A cuboid's opposing faces are always equal. It indicates that the cuboid's opposing surfaces are in the same dimension. The cuboid can be measured in terms of its volume, lateral or curved surface area, and total surface area (TSA). The volume of the cube is measured in cubic units, whereas the surface areas are measured in square units.

Here, according to the given information, we are given that,

The dimensions of the cuboidal tin are,

Length (l) = 30 cm.

Breadth (b) = 40 cm.

Height (h) = 50 cm.

Then, total surface area $= 2(lb + bh + lh)$.

Then, we get,

Total surface area = $2(30.40+40.50+30.50) = 2(1200+2000+1500) = 2(4700)= 9400cm^{2}$.

Then, total surface area of 20 tins = 20 × 9400 = 188000 cm².

1 m² = 10000 cm² costs Rs. 20.

Then, 1 cm² costs Rs. $\frac{20}{10000}$

Then, 9400 cm² costs Rs. $\frac{2}{1000} .9400 = 18.8$ Rs.

Hence, the cost of tin required for making 20 such tins is Rs. 18.8

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