Question

A cuboidal room with the length 'l', breadth 'b' and height 'h' has area of 4 walls as​

Answer 1

Answer:

It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.

Area of four walls of the room is: 2h(l+b)

A=2h(l+b)=2×3(8+5)=6×13=78 m

2

Area of the ceiling is:

A=l×b=8×5=40 m

2

Total area of the four walls and the ceiling of the room is 78+40=118 m

2

It is given that cost of white washing is Rs.15/m

2

, therefore,

Total cost of white washing is:

118×15=1770

Hence, the cost of white washing the walls is Rs.1770

Answer 2

Answer:

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Area of the 4 walls= 2bh+ 2hl

= 2h( l+b) cm²