Question

A cuboidal tin box has dimensions l cm × b cm × h cm. What is the total surface area of metal sheet required to make 10 such boxes?

Answer 1

Step-by-step explanation:

Answer:-

Given that Cuboidal Tin box has dimentions .

Concept:-

Application of TSA or Total Surface Area.

Let's Do!

• Given that length is l.
• Given that breadth is b.
• Given that height is h.

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl)}}$

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl)}}$ Same, as dimentions given are also same.

Now, we need 10 such boxes. So, we will multiply it with 10.

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl) \times 10}}$

$\boxed{\sf{ TSA \ Cuboid = 20(lb+bh+hl)}}$ is the required answer.

More to Know:-

• CSA of a Cuboid is $\sf{2(l+b) \times h}$
• Volume is $\sf{l \times b \times h}$
• Here, l, b and h are same.

Answer 2

$\huge\sf\boxed{\green{Question:-}}$

A cuboidal tin box has dimensions l cm × b cm × h cm. What is the total surface area of metal sheet required to make 10 such boxes?

$\huge\green{ \underline{ \boxed{ \sf{solution-}}}}$

⟾Given that length is l.

⟾Given that breadth is b.

⟾Given that height is h.

T.S.A of cuboid=2(lb+bh+hl)

Same, as dimentions given are also same.

Now, we need 10 such boxes. So, we will multiply it with 10.

T.S.A of cuboid=2(lb+bh+hl)×10

⇒20(lb+bh+hl)

➥the required answer is 20(lb+bh+hl)

➜hence proved✔

➾hope you get the answer