Question

A cuboidal tin box has dimensions l cm × b cm × h cm. What is the total surface area of metal sheet required to make 10 such boxes?


Need full explanation!​

Answer 1

$\huge \sf {\orange {\underline {\pink{\underline{Answer :-}}}}}$

Given that Cuboidal Tin box has dimentions .

$\huge \sf {\orange {\underline {\pink{\underline{Concept\:used :-}}}}}$

Application of TSA or Total Surface Area.

• Given that length is l.
• Given that breadth is b.
• Given that height is h.

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl)}}$

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl)}}$ Same, as dimentions given are also same.

Now, we need 10 such boxes. So, we will multiply it with 10.

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl) \times 10}}$

$\boxed{\sf{ TSA \ Cuboid = 20(lb+bh+hl)}}$ is the required answer.

${\huge{\underline{\small{\mathbb{\pink{HOPE\:HELPS\:UH :)}}}}}}$

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Answer 2

$\huge \sf {\orange {\underline {\pink{\underline{Answer :-}}}}}$

Given that Cuboidal Tin box has dimentions .

$\huge \sf {\orange {\underline {\pink{\underline{Concept\:used :-}}}}}$

Application of TSA or Total Surface Area.

• Given that length is l.
• Given that breadth is b.
• Given that height is h.

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl)}}$

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl)}}$ Same, as dimentions given are also same.

Now, we need 10 such boxes. So, we will multiply it with 10.

$\boxed{\sf{ TSA \ Cuboid = 2(lb+bh+hl) \times 10}}$

$\boxed{\sf{ TSA \ Cuboid = 20(lb+bh+hl)}}$ is the required answer.

${\huge{\underline{\small{\mathbb{\pink{HOPE\:HELPS\:UH :)}}}}}}$