Question

A cuboidal tin box open at the top has dimensions 20 cm into 16 cm into 14 cm what is the total area of metal sheet required to make 10 such boxes

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The total area of metal sheet required to make 10 such boxes is 13280 sq.cm.

Step-by-step explanation:

Length of box = 20 cm

Breadth of box = 16 cm

Height of box = 14 cm

Lateral surface area of box and one base = 2(l+b)h +lb

                                                                     = $2(20+16)(14)+(20 \times 16)$

                                                                     =$1328 cm^2$

Metal sheet required for 1 box = 1328 sq.cm.

Metal sheet required for 10 boxes = $1328 \times 10 = 13280 cm^2$

Hence the total area of metal sheet required to make 10 such boxes is 13280 sq.cm.

#Learn more:

The dimensions of a cuboidal tin are 30 cm*40 cm* 50 cm. Find the cost of tin required for making 20 such tins, if the cost of tin sheet is ₹20 per square metre.

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